jonasgessner / jgprogresshud-swiftui Goto Github PK

As I see the current state of art, I need to do dismiss(afterDelay: ) with the hud. What about dismissing it with when there is a change in a property of a view model. Let's say I want to hide after fetching is completed. I am doing it this way, I don't know whether it is a good approach or not.

           hudCoordinator.showHUD {
                    let hud = JGProgressHUD()
                    hud.textLabel.text = "Fetching Profile Details....."
                    hud.textLabel.font = UIFont(name: FontConstants.poppinsMedium, size: 12)
                    hud.backgroundColor = UIColor(white: 0, alpha: 0.4)
                    viewModel.$fetchedCompleted.sink { completed in
                        if completed {
                            hud.dismiss()
                        }
                    }.store(in: &viewModel.subscription)
                    return hud
                }

Can anybody guide me with this?

As title.

The ContentView is wrapped with JGProgressHUDPresenter and showing some HUDs, presenting a .sheet page (eg.: some PreferencesView) which is also wrapped with another JGProgressHUDPresenter. Calling show() in the sheet page only shows the HUD in the content view, behind the sheet view itself. (observed from Xcode view hierarchy)
Passing the hudCoordinator from ContentView to .sheet(), instead of wrapping .sheet with JGProgressHUDPresenter, does not help.
Any ideas on this? Or is there another (correct) way to show the HUD? Thanks!
(Falling back to use objc JGProgressHUD now)