剑指Offer题目代码完全实现
wang-jun-chao / coding-interviews Goto Github PK
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剑指Offer
// 递归求一半的值
double result = powerWithUnsignedExponent(base, exponent >> 2);
这里应该是右移一位,改为
double result = powerWithUnsignedExponent(base, exponent >> 1);
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谢谢
饿汉式和懒汉式是否应互换一下?
coding-interviews/src/Test28.java
tmp = chars[begin];
chars[begin] = chars[i];
chars[i] = tmp;
// 处理下一个位置
permutation(chars, begin + 1);
//permutation(chars, begin + 1);后添加代码:
tmp = chars[i];
chars[i] = chars[begin];
chars[begin] = tmp;
如遇乱码,请参考。
powerWithUnsignedExponent(base, exponent >> 2);
应该是1
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