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I Want to Copy a NXP Semiconductors ICODE SLIX-S HC (SL2S5402) tag

I'm new to this area and I think the PN5180 is the compatible reader that I could copy and write to another ISO 15693. Looking at this HTML that I took with my phone, can you tell me if it's possible to make the copy?

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4.27.0

2023-08-31 09:50:18

<title>NXP Semiconductors ICODE SLIX-S HC (SL2S5402) tag</title>

3F:C2:1F:03:D0:02:04:E0

false

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NXP Semiconductors

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ICODE SLIX-S HC (SL2S5402)

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Maximum NDEF storage size after format: 154 bytes

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160 bytes ‣ 10 pages, with 4 blocks per page ‣ 40 blocks, with 4 bytes per block

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Supported read commands: ‣ Single Block Read ‣ Inventory Page Read ‣ Fast Inventory Page Read ‣ Get Multiple Block Protection Status ‣ Get System Information AFI supported DSFID supported IC reference value: 0x02 Capacitance: 23.5 pF

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Electronic Article Surveillance (EAS) active

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Version :4.27.0

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Device Model :samsung ( SM-S901E ) Android OS Version :13

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ISO/IEC 15693-3 compatible ISO/IEC 15693-2 compatible

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Tag description: ‣ TAG: Tech [android.nfc.tech.NfcV, android.nfc.tech.NdefFormatable] ‣ Maximum transceive length: 253 bytes
MIFARE Classic support present in Android

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ID: E0:04:02:D0:03:1F:C2:3F AFI: 0x00 DSFID: 0x00

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0

AB FB FD 45

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1

89 0C 20 D0

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2

4E 20 B4 F4

-

3

0F A6 5E 4B

-

4

5E 9D 49 01

-

5

14 6E EF 4A

-

6

8E 75 5F 8B

-

7

E1 DF C5 1A

-

8

B8 6D 01 29

-

9

AC 4E 93 90

-

10

99 CC 01 01

-

11

C4 00 00 07

-

12

57 08 80 C4

-

13

00 00 00 00

-

14

00 00 00 00

-

15

00 00 00 00

-

16

00 00 00 00

-

17

00 00 00 00

-

18

00 00 00 00

-

19

00 00 00 00

-

20

00 00 00 00

-

21

2D 71 44 08

-

22

15 55 52 49

-

23

24 90 00 00

-

24

00 00 2E 00

-

25

00 00 00 00

-

26

00 00 00 00

-

27

13 80 33 29

-

28

13 80 2F 2B

-

29

13 80 0E 2B

-

30

13 80 0D 2D

-

31

13 80 08 43

-

32

13 80 07 2B

-

33

13 80 06 2A

-

34

17 85 DF 2C

+

-

36

02 00 C5 2F

-

37

19 48 60 22

-

38

01 14 45 69

-

39

20 00 97 51

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r:readable, w:writeable, -/=:password protected, .:un(b)locked,*:locked & blocked, x:locked, +:blocked

I²C

Hello,

Is there example for the I²C bus for this IC?

Thank you

I can't compile the example

Hello!
I'm trying to run a demo example in Arduino IDE 2.2.1,
renamed CLRC663-Demo.ino.cpp to CLRC663-Demo.ino
When compiling, an error is thrown -
c:\Users..\Documents\Arduino\libraries\CLRC663-Library-main\CLRC663.cpp: In member function 'void CLRC663::begin()':
c:\Users..\Documents\Arduino\libraries\CLRC663-Library-main\CLRC663.cpp:87:36: error: no matching function for call to 'TwoWire::begin(byte&, byte&)'
_wire->begin(pinSDA, pinSCL);
^
In file included from c:\Users..\Documents\Arduino\libraries\CLRC663-Library-main\CLRC663.h:5:0,
from c:\Users..\Documents\Arduino\libraries\CLRC663-Library-main\CLRC663.cpp:18:
C:\Users..\AppData\Local\Arduino15\packages\arduino\hardware\avr\1.8.6\libraries\Wire\src/Wire.h:53:10: note: candidate: void TwoWire::begin( )
void begin();
^~~~~
C:\Users..\AppData\Local\Arduino15\packages\arduino\hardware\avr\1.8.6\libraries\Wire\src/Wire.h:53:10: note: candidate expects 0 arguments, 2 provided
C:\Users..\AppData\Local\Arduino15\packages\arduino\hardware\avr\1.8.6\libraries\Wire\src/Wire.h:54:10: note: candidate: void TwoWire::begin( uint8_t)
void begin(uint8_t);
^~~~~
C:\Users..\AppData\Local\Arduino15\packages\arduino\hardware\avr\1.8.6\libraries\Wire\src/Wire.h:54:10: note: candidate expects 1 argument, 2 provided
C:\Users..\AppData\Local\Arduino15\packages\arduino\hardware\avr\1.8.6\libraries\Wire\src/Wire.h:55:10: note: candidate: void TwoWire::begin( int)
void begin(int);
^~~~~
C:\Users..\AppData\Local\Arduino15\packages\arduino\hardware\avr\1.8.6\libraries\Wire\src/Wire.h:55:10: note: candidate expects 1 argument, 2 provided
c:\Users..\Documents\Arduino\libraries\CLRC663-Library-main\CLRC663.cpp: In member function 'void CLRC663::begin(int, int)':
c:\Users..\Documents\Arduino\libraries\CLRC663-Library-main\CLRC663.cpp:94:12: error: 'class TwoWire' has no member named 'setPins'
_wire->setPins(sda, scl);
^~~~~~~

What did I do wrong?

I apologize for the length of text and the possible obviousness of the answer.

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