terezka / yaml Goto Github PK

I came across this package because I need to parse and generate YAML in Elm. I want to ask about contribution guidelines, mainly:

1. Is it intentional that the package doesn't have package.json with dev deps to run tests?
2. Is it intentional that elm.json doesn't have test deps either?
3. When I set up testing I found several failing tests - is it just me or is it failing in general?
4. What version of elm-format is used?

I tried to parse the following YAML:

  - name: GARLIC
    units: 
      - clove
      - grams
  - name: "GARLIC POWDER"
    units: 
      - grams

For some reasons GARLIC is parsed as garlic (lowercase) while GARLIC POWDER is parsed in uppercase.

As a fix, I used the following parser:

(Decode.field "name"
    (Decode.string
        |> Decode.andThen (String.toUpper >> Decode.succeed)
    )
)

Hi, I've run into an error I can't seem to get around -- could just be me, but here is a stripped down version. The problem arises with code like

decodeItem : Decoder ( String, Int )
decodeItem =
    Decode.string
        |> Decode.andThen baz

I've reduced baz to a bare minimum, so that it always succeeds, always returning the same thing:

baz : String -> Decoder ( String, number )
baz =
    \s -> Decode.succeed ( "Test", 88 )

Here is the error:

↓ VerifyExamples.Yaml.DecodeItem0
✗ #decodeItem:

    Decode.fromString decodeItem "(Test:88)"
    --> Ok ("Test", 88)

    Ok ("Test",88)
    ╷
    │ Expect.equal
    ╵
    Err (Parsing "TODO deadEndsToString")

And here is the test code:

{-|

    import Yaml.Decode as Decode exposing (Decoder)

    Decode.fromString decodeItem "(Test:88)"
    --> Ok ("Test", 88)

-}
decodeItem : Decoder ( String, Int )
decodeItem =
    Decode.string
        |> Decode.andThen baz

Hi!

Is there a way to decode optional fields? Something like Json.Decode’s maybe?