Hi, I'm a high schooler who is interested in quantum physics and quantum computing. I have a very limited understanding of quantum computing at the moment, and I'm having trouble understanding how your QRNG design produces random numbers. This is how I understand your device:
As you stated in your article, there are trillions of photons in each light pulse. Each individual photon has a 50% chance to collapse into a vertical or horizontal state. As an example, assuming exactly 1 trillion photons pass through, approximately 500 billion photons would be vertically polarized, and approximately 500 billion would be horizontally polarized. Photoresistors of the type used in this device are not able to detect light to the photon level, so, in theory, both resistors should provide a resistance with an unmeasurable difference. Any measurable difference in voltage would be caused by background light, imperfectly angled sensors, dark counts, or variance within the measuring tool. As far as I understand, what actually is happening is RNG created by radiation/noise from the background or from the hardware, which, while it should be truly random, is not quantum randomness. Another implication is that using an expensive polarized beamsplitter is completely unnecessary in that case, as a cheaper non polarized 50/50 beamsplitter would work just fine.
I just re-read the original article and found you were originally using a 650nm red laser diode. If I recall correctly, lasers emit polarized light, meaning that the quantum state of the photons is already collapsed at the moment of leaving the laser, making the entire RNG pointless. I'm not sure if the same is true with LEDs though. Anyway, the point is, as far as I understand it, single photon generation and detection is required for this form of quantum number generation. However, I am still just a high school student with very little knowledge about quantum physics, so I'm very likely wrong about this whole thing. It'd be great if you could clarify what I'm missing here.
Final note: I am almost completely confident of this: one cannot perform a Hadamard transform on more than a single photon at a time and it would not be able to return the superposition measurement (I assume that is what you mean by qubit angle? though I'm not sure what you mean by angle... is it the angle of the linear combination of basis states vectors?). A measurement after a Hadamard transform would just collapse it back to a single classical state and not give a measurement of the entangled state as far as I'm aware.