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primowenjoy avatar primowenjoy commented on September 18, 2024 1
    private <ENTITY> PredicateMapping equal(
        final Criteria<ENTITY, ?> criteria,
        final FieldPredicate<ENTITY> fieldPredicate
    ) {
        Class<?> clazz = Object.class;
        if (fieldPredicate instanceof HasArg0) {
            clazz = ((HasArg0<?>) fieldPredicate).get0().getClass();
        }
        return typeMapping(
            criteria,
            fieldPredicate,
            createParameterizedPredicate(
                (column, parameter) -> criteria.getBuilder().equal(criteria.getRoot().get(column), parameter)
            ),
            clazz
        );
    }

I find a way to workaround this. However, as I am not familiar with its internal logic, i am not sure if it's a decent way.
Instead of directly using Object.class, we can get a more concrete class info via HasArg0 interface.

from jpa-streamer.

alenaSchuh avatar alenaSchuh commented on September 18, 2024 1

I also encountered this issue, but with Strings:
Cannot compare left expression of type 'java.lang.String' with right expression of type 'java.lang.Object
Right expression is just a normal String in our code.

from jpa-streamer.

primowenjoy avatar primowenjoy commented on September 18, 2024

I have also stumped on this issue.

from jpa-streamer.

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