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View Code? Open in Web Editor NEWDependently-typed language w/ little to say for itself
License: BSD 3-Clause "New" or "Revised" License
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The Sigma constructor does not typecheck
I don’t know when this broke exactly, but Sigma no longer typechecks:
λ: runCommand (Surface.Command.Run "src/Prelude.surf")
Cannot unify A -> Type with Type
Execution trace as of 34873fb
(checkDeclaration Prelude.Sigma, { g3, [] })
(isType (A -> (A -> Type) -> Type), { g3, [] })
(isType Type, { g3, [] })
(isType ((A -> Type) -> Type), { g3, [ A :: Type ] })
(isType (A -> Type), { g3, [ A :: Type ] })
(isType A, { g3, [ A :: Type ] })
(isType Type, { g3, [ A :: Type ] })
(isType Type, { g3, [ A :: Type, _ :: A ] })
(isType Type, { g3, [ A :: Type, B :: (A -> Type) ] })
(checkConstructor Prelude.Sigma.sigma, { g3, [] })
(fresh Type, { g3, [ ; ] })
(fresh (A -> Type), { h3, [ ;, g3 := Type ] })
(infer (A -> (B : (A -> Type)) -> (a : A) -> B a -> Sigma A B), { i3, [ ;, g3 := Type, h3 := (A -> Type) ] })
(infer ((B : (A -> Type)) -> (a : A) -> B a -> Sigma A B), { i3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type ] })
(infer ((a : A) -> B a -> Sigma A B), { i3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type) ] })
(infer (B a -> Sigma A B), { i3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A ] })
(infer (Sigma A B), { i3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a ] })
(infer B, { i3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a ] })
(fresh A, { i3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a ] })
(fresh _, { j3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A ] })
(check (Sigma A) (Type -> j3), { k3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
(infer (Sigma A), { k3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
(infer A, { k3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
(fresh _, { k3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
(check Sigma (Type -> k3), { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := _ ] })
(unify (A -> (A -> Type) -> Type) (Type -> k3), { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := _ ] })
(unify Type Type, { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := _ ] })
(unify ((A -> Type) -> Type) k3, { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := _ ] })
(solve k3 [] ((A -> Type) -> Type), { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := _ ] })
(replace [ k3 := ((A -> Type) -> Type) ], { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
(unify (Type -> j3) k3, { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := ((A -> Type) -> Type) ] })
(solve k3 [] (Type -> j3), { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _, k3 := ((A -> Type) -> Type) ] })
(unify ((A -> Type) -> Type) (Type -> j3), { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
(unify (A -> Type) Type, { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })
([ "Cannot unify A -> Type with Type", "" ], { l3, [ ;, g3 := Type, h3 := (A -> Type), A :: Type, B :: (A -> Type), a :: A, _ :: B a, i3 := A, j3 := _ ] })Data constructors with the same names as type constructors don’t infer correctly
E.g. if you rename the constructor these :: l -> r -> These l r to These :: l -> r -> These l r, its type can no longer be inferred.
I think the data constructor is overwriting the type constructor in the environment.
Typechecking errors don’t tell you the line and column
I think we’re going to want to use a Cofree structure for Expr to accomplish this.
Parsing errors are hidden in --debug mode
There is no comment syntax
Comment syntax like -- … \n and/or {- … -} would be good. Ideally we should also have some sort of annotation syntax for e.g. checked doc comments, but I think we can leave that til later.
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