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Comments (2)

rfindler avatar rfindler commented on August 19, 2024

Yes. This works, for example:

#lang racket
(require redex/reduction-semantics)

(define-language L
  (n ::= Z (S n)))

(define-judgment-form L
  #:mode (odd I)

  [(even n)
   ----------
   (odd (S n))])


(define-judgment-form L
  #:mode (even I)

  [--------
   (even Z)]
  
  [(odd n)
   ------------
   (even (S n))])


(test-judgment-holds (even Z))
(test-judgment-holds (odd (S Z)))
(test-judgment-holds (even (S (S Z))))
(test-equal (judgment-holds (odd Z)) #f)
(test-equal (judgment-holds (even (S Z))) #f)
(test-results)

from redex.

mbuszka avatar mbuszka commented on August 19, 2024

Thank you!

from redex.

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