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Hi,

I am trying to do a functionality in which I would be getting updated when any user logsin to chat or logsout of chat. As per the documentation ( in https://quickblox.com/developers/Android_XMPP_Chat_Sample), I have implemented groupChatDialog.addParticipantListener(participantListener) for getting update if any user sends the subscription request through "chatRoster.subscribe(userID)" is done by any other user and in callback function it accepts the subscription through confirmSubscription function.

But what would happen when the user to which we have sent subscription request is offline is not clear.
I debugged and saw that the collection which we get through chatRoster.getEntries() gives us the list of all users which have requested as well as which have confirmed our subscription but I am not getting any updates for presence of the users which have pending confirmation. Further I searched for any documentation regarding this but I haven't found anything. How to handle this situation?

Hi, we use quickblox in our application. Some functions require store user info in our databases. We want to use method reset pasword through our servers, but as wrote in your rest api, it possible if user remember his old password or he can make it through email. But we doesn't use email in user model.

Is it possible to change user password without remember old password or using email? As it work in QB web admin panel.

Hi,

We have been following quickBlox documents for creating signature to be used for Rest API "https://api.quickblox.com/session.json" with body as
" {"application_id":"62009", "auth_key":"5aEUnVvFRSEfDeb", "timestamp": "1505802326", "nonce": "33533", "signature":"afb700e027914f6877809c6c3d46a5f7416a7077"}"

and response is

{
"errors": {
"base": [
"Unexpected signature"
]
}
}

The code for generating the signature is as follow in java

public class HmacSha1Signature {

public static void main(String[] args) throws Exception {
	 String signature_string ="application_id=62009&auth_key=5aEUnVvFRSEfDeb&nonce=33532&timestamp=1505802326&user[login]=9891518265&user[password]=123";
    System.out.println(hmacDigest(signature_string, "6EESPASrHQ9VnCp", "HmacSHA1"));
  }

  public static String hmacDigest(String msg, String keyString, String algo) {
    String digest = null;
    try {
      SecretKeySpec key = new SecretKeySpec((keyString).getBytes(), algo);
      Mac mac = Mac.getInstance(algo);
      mac.init(key);

      byte[] bytes = mac.doFinal(msg.getBytes("ASCII"));

      StringBuffer hash = new StringBuffer();
      for (int i = 0; i < bytes.length; i++) {
        String hex = Integer.toHexString(0xFF & bytes[i]);
        if (hex.length() == 1) {
          hash.append('0');
        }
        hash.append(hex);
      }
      digest = hash.toString();
    } catch (UnsupportedEncodingException e) {
    } catch (InvalidKeyException e) {
    } catch (NoSuchAlgorithmException e) {
    }
    return digest;
  }

}

Further I am attaching the screen shot of postman response. Could you please tell us what we are doing wrong to create signature?