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Day 3 of 2022: Switch away from nested for loops

adventofcode/2022/day03/day03/__init__.py

Lines 37 to 45 in 98b1b79

 def find_badge_between_rucksacks(list_of_three_rucksacks:List[str]) -> str: 

 """Find the common badge between Rucksack objects""" 

 first_rucksack, second_rucksack, third_rucksack = list_of_three_rucksacks 

 #print(f'Rucksacks:\nFirst = {first_rucksack.items}\nSecond = {second_rucksack.items}\nThird = {third_rucksack.items}') 

 for item_list_one in first_rucksack.items: 

 for item_list_two in second_rucksack.items: 

 for item_list_three in third_rucksack.items: 

 if item_list_one == item_list_two == item_list_three: 

 return item_list_one

A good tip from a fellow Pythonista is to use set intersection to find the common item (character) between multiple rucksacks. I'll work on this when I can.

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	def find_badge_between_rucksacks(list_of_three_rucksacks:List[str]) -> str:
	"""Find the common badge between Rucksack objects"""
	first_rucksack, second_rucksack, third_rucksack = list_of_three_rucksacks
	#print(f'Rucksacks:\nFirst = {first_rucksack.items}\nSecond = {second_rucksack.items}\nThird = {third_rucksack.items}')
	for item_list_one in first_rucksack.items:
	for item_list_two in second_rucksack.items:
	for item_list_three in third_rucksack.items:
	if item_list_one == item_list_two == item_list_three:
	return item_list_one

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