pr0crustes / bignumber Goto Github PK
View Code? Open in Web Editor NEWA really long long long long long long number in C++
License: MIT License
A really long long long long long long number in C++
License: MIT License
when I calculate this:
BigNumber(0) - BigNumber(3)*BigNumber(4)
it is return 12.
In your code:
BigNumber operator-(const BigNumber& number) const noexcept(true) {
if (this->isPositive() && !number.isPositive()) {
return *this + number.absoluteValue();
} else if (!this->isPositive() && number.isPositive()) {
return -(number + this->absoluteValue());
}
if (number.isZero()) {
return *this;
}
if (this->isZero()) {
return number;
}
this should be:
if (this->isZero()) {
return -number;
}
Right now the modPow method just takes the modulus after every multiplication.
This can be made thousands of times faster, especially for large numbers.
This clever method is shown at this link: https://www.khanacademy.org/computing/computer-science/cryptography/modarithmetic/a/fast-modular-exponentiation
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