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The function cnf-to-ddnnf can convert a formula encoded in CNF into d-DNNF.

d-DNNF is an encoding of logic formulas conforming to certain rules:

1. all negations are at the leaves.
2. in all OR nodes, exactly one sub-clause is true, called 'deterministic'.
3. the set of variables appearing in a sub-clause of an AND node does not overlap with those of a different sub-clause of the same AND node, called decomposable.

d-DNNF's are a relatively compact representation of all solutions of a CNF, at least more compact than listing all solutions.

It uses very similar techniques DPLL solvers use:

• identify unit clauses
• split by assuming values for variables according to some simple heuristics
• separately solve independent partitions of a large cnf

one-of-three written in CNF as

(a or b or c)
  and (not a or not b)
  and (not a or not c)
  and (not b or not c)

is encoded as

((1 2 3) (-1 -2) (-1 -3) (-2 -3))

and converted to d-DNNF by

CL-USER> (cnf-to-ddnnf '((1 2 3) (-1 -2) (-1 -3) (-2 -3)))

(OR (AND 2 -1 -3) (AND -2 (OR (AND 1 -3) (AND -1 3))))

CL-USER> (cnf-to-ddnnf '((1 2 3) (-3 4 5)))

(OR (AND 3 (ND-OR 4 5) (INDEPENDENT 1 2))
    (AND -3 (ND-OR 1 2) (INDEPENDENT 4 5)))

• OR nodes are deterministic, i.e. by construction only one of the OR arguments is true
• AND nodes are decomposable
• ND-OR nodes are non-deterministic OR nodes. A shortcut for trivially expanded OR. Only used at the leaves for a syntactically shorter result.
• INDEPENDENT nodes are nodes allowing any truth value for the given variables. Another shortcut that can be trivially expanded. Only used at the leaves for a syntactically shorter result.

Code should load in any Common Lisp environment, use

(load "dpll.lisp")
(load "ddnnf.lisp")

Are the produced d-DNNF's really smooth?