- This was part of a project when I was student at University of The Azores.
- The code works with python 3.6
- The code may contain portuguese language
- The Python file contains a GUI, created with the library Tkinter.
The portuguese ID, known in Portugal as Cartão de cidadão, is the first part of the code.
The algorithm is in the pdf file along with this post and has an example code in C#. Since we were learning Python 3, we had to translate the C# code into pyhton.
if you want only the function I create to validate the ID/CC, you can copy the following code:
def verificacao():
listaalfa = ['0','1','2','3','4','5','6','7','8','9','a','b','c','d','e','f','g','h','i','j','k','l','m','n','o','p','q','r','s','t','u','v','w','x','y','z']
listanum = [0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24,25,26,27,28,29,30,31,32,33,34,35]
cc1 = input()
cc = cc1.lower()
print(cc)
soma = 0
if len(cc) != 12:
print('numero de cartao de cidadao invalido')
else:
for i in range (len(cc)-1,-1,-1):
if i % 2 == 0:
if cc[i] in listaalfa:
pos = listaalfa.index(cc[i])
soma += listanum[pos]*2
if listanum[pos]*2 >= 10:
soma -= 9
else:
if cc[i] in listaalfa:
pos = listaalfa.index(cc[i])
soma += listanum[pos]
soma = soma % 10
if soma == 0:
print('cartao de cidadao valido')
else:
print('cartao de cidadao invalido')
The NIF, known in Portugal as Numero de Identificação Fiscal, or Fiscal Code, was made with the guide of the portuguese wikipedia (https://pt.wikipedia.org/wiki/N%C3%BAmero_de_identifica%C3%A7%C3%A3o_fiscal).
if you want only the python code:
def verificacao():
nif = input()
soma = 0
verificacao = 0
if len(nif) != 9:
print('invalido')
return
index = 7
for i in range(2,10):
soma += int(nif[index])*i
index -= 1
verificacao = soma % 11
if verificacao == 0 or verificacao == 1:
verificacao = 0
else:
verificacao = 11 - verificacao
if verificacao == int(nif[8]):
print('valido')
else:
print('invalido')
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