解决 ListView
嵌套ListView
问题
NestListView
继承自 Linearlayout
通过 addView
来构造出类似 ListView
样式
http://www.jianshu.com/p/b805091bd4e5
http://blog.csdn.net/lmj623565791/article/details/38902805/
直接拷贝 NestListView.java
和 CacheHolder.java
对外层的 ListView
的 Adapter
添加并实现该 NestListView.BindViewGroupListene
接口即可,如下:
public class xxAdapter extends BaseAdapter implements NestListView.BindViewGroupListener{
....
....
@Override
public View getView(int position, View convertView, ViewGroup parent) {
ViewHolder viewHolder = null;
...
...
viewHolder.mNestListView.setBindViewGroupListener(this);// 绑定当前实现的接口
viewHolder.mNestListView.setReuse(true);// 开启重用机制
viewHolder.mNestListView.createNestListView(position,data.size());// 开始创建具体的 NestListView
return convertView;
}
//该方法和重写 BaseAdapter 的 getView 类似
@Override
public View getNestView(int positionInList, int positionInNestList, View convertView){
NestListViewHolder nestListHolder = null;
if (convertView == null){
convertView = LayoutInflater.from(mContext)
.inflate(R.layout.nest_list_item, null);
// 缓存所有 convertView 下的小 view 的实例对象,避免重复 findViewById
nestListHolder = new NestListViewHolder(convertView);
convertView.setTag(nestListHolder);
} else {
nestListHolder = (NestListViewHolder) convertView.getTag();
}
...
nestListHolder.mTextView.setText(url);
...
return convertView;
}
}
具体可以参考ListBaseAdapter.java