connuh / tiktok-api Goto Github PK
View Code? Open in Web Editor NEWLightweight & fast TikTok API centralised around the Android API!
License: GNU General Public License v3.0
Lightweight & fast TikTok API centralised around the Android API!
License: GNU General Public License v3.0
If yes, how to get the session?
re-encryption is wrong
Encryption.getHeaders
apparently uses the previous request
and the server returns an empty body
BASE_URL: "https://api2.musical.ly"
exemple:
max_cursor=0
aweme/v1/aweme/post/?count=20&retry_type=no_retry&user_id=6906899892594590725&max_cursor=0&address_book_access=1&from=0&os_api=25&device_type=G011A&ssmix=a&manifest_version_code=2022004060&dpi=270&carrier_region=US&uoo=0®ion=US&app_name=musical_ly&version_name=20.4.6&timezone_offset=28800&ts=1627073538&ab_version=20.4.6&residence=US&cpu_support64=false¤t_region=US&ac2=wifi&ac=wifi&app_type=normal&host_abi=armeabi-v7a&channel=googleplay&update_version_code=2022004060&_rticket=1627073538571&device_platform=android&iid=6987910945902085893&build_number=20.4.6&locale=en&op_region=US&version_code=200406&timezone_name=Asia%2FShanghai&cdid=ef81b614-49a5-44c6-afce-a7f37c4068cb&openudid=a2fe20e27715a0c2&sys_region=US&device_id=6987910663994934789&app_language=en&resolution=810*1440&device_brand=google&language=en&os_version=7.1.2&aid=1233&mcc_mnc=31031
in this case I get the correct answer
max_cursor=1632670040000
aweme/v1/aweme/post/?count=20&retry_type=no_retry&user_id=6906899892594590725&max_cursor=1632670040000&address_book_access=1&from=0&os_api=25&device_type=G011A&ssmix=a&manifest_version_code=2022004060&dpi=270&carrier_region=US&uoo=0®ion=US&app_name=musical_ly&version_name=20.4.6&timezone_offset=28800&ts=1627073538&ab_version=20.4.6&residence=US&cpu_support64=false¤t_region=US&ac2=wifi&ac=wifi&app_type=normal&host_abi=armeabi-v7a&channel=googleplay&update_version_code=2022004060&_rticket=1627073538571&device_platform=android&iid=6987910945902085893&build_number=20.4.6&locale=en&op_region=US&version_code=200406&timezone_name=Asia%2FShanghai&cdid=ef81b614-49a5-44c6-afce-a7f37c4068cb&openudid=a2fe20e27715a0c2&sys_region=US&device_id=6987910663994934789&app_language=en&resolution=810*1440&device_brand=google&language=en&os_version=7.1.2&aid=1233&mcc_mnc=31031
and here is an empty body
the function retains the previous request
How does the API posting work for the username? What arguments do you need in the post form? I'd like to use this api, but im better at python than javascript.
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