Your task is to write a function that simplifies the business hours of a store. You will be provided with an array of JSON objects representing the hours of operation for each day of the week. Your function should return a string that represents the simplified version of the business hours.

You will receive an array of objects. Each object contains:

• dayOfWeek: The day of the week as a string (e.g., "Montag", "Dienstag", etc.)
• from: The opening time of the store in HH:MM:SS format
• to: The closing time of the store in HH:MM:SS format

[
  {"dayOfWeek": "Montag", "from": "07:00:00", "to": "22:00:00"},
  {"dayOfWeek": "Dienstag", "from": "07:00:00", "to": "22:00:00"},
  ...
]

Your function should return a string that condenses the business hours into a simplified representation.

"Mo-Di 10:00 - 20:00, Mi-Do 09:00 - 18:00, Fr-So 09:00 - 14:00"

• The days will be sorted in the order: Montag, Dienstag, ..., Sonntag.
• The time will be in 24-hour format.

	data := `[{"dayOfWeek": "Montag", "from": "10:00:00", "to": "20:00:00"},
	          {"dayOfWeek": "Dienstag", "from": "10:00:00", "to": "20:00:00"},
	          {"dayOfWeek": "Mittwoch", "from": "09:00:00", "to": "18:00:00"},
	          {"dayOfWeek": "Donnerstag", "from": "09:00:00", "to": "18:00:00"},
	          {"dayOfWeek": "Freitag", "from": "09:00:00", "to": "14:00:00"},
	          {"dayOfWeek": "Samstag", "from": "09:00:00", "to": "14:00:00"},
	          {"dayOfWeek": "Sonntag", "from": "09:00:00", "to": "14:00:00"}]`

"Mo-Di 10:00 - 20:00, Mi-Do 09:00 - 18:00, Fr-So 09:00 - 14:00"

• Consider using a loop to iterate through the days and group the ones with the same business hours.
• Keep track of sequences (consecutive days with the same hours) to simplify the output.

• Correctness: Does the code perform as required?
• Readability: Is the code easy to follow?
• Simplicity: Is the code straightforward and concise?

Good luck and happy coding! 🎉