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CharlieDinh avatar CharlieDinh commented on July 21, 2024

Hi siddharthdivi,
Mu in here is a kind of regularization inside f_i(\theta).
For example: The local optimization problem for each client is defined as $theta_i = min( f_i(\theta_i) + \frac{\lamda}{2}(theta_i -w))$. I can consider the f_i(\theta_i) is cross entropy loss function with regularization $\frac{mu}{2}(theta_i)^2$ inside. So here $\mu$ is regularization term to make f_i function becomes strongly-convex

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siddharthdivi avatar siddharthdivi commented on July 21, 2024

Thanks for the explanation!

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