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pedestrian-counter's Introduction

Pedestrian Counting Using OpenCV 3.1 in Python

Prerequisites

  • You can download the TownCentre dataset used for demonstration here
  • Update This dataset is now unavailable online due to the privacy risks
  • Conda installed

Instructions

  • Added a conda env to easily set this up on your machine
  • Just run:
conda env create -f ./env.yaml
conda activate pedestrian-counter
python pedestrian.py

pedestrian-counter's People

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pedestrian-counter's Issues

Line cross

return y - (29*x)/96.0 - 300

i have tried to understand but didn't get anything
Can you please explain why "29" and "96" is used?

def line1(x,y) and def line2(x,y)

Hi @anandsinghkunwar, can you explain to me more about this lines of code?

def line1(x,y):
    return y - (29*x)/96.0 - 300

def line2(x,y):
    return y - (29*x)/96.0 - 500

I believe its related to this code (create two lines on the frame)

    cv2.line(frame, (0,300), (1920,880), (255, 0, 0), 4)
    cv2.line(frame, (0,500), (1920,1080), (255, 0, 0), 4)

If I want to change the code above to (which is two lines transverse the frame)

    cv2.line(frame, (0,100), (500,100), (255, 0, 0), 4)
    cv2.line(frame, (0,200), (500,200), (255, 0, 0), 4)

How can I modify the function line1() and line2()

Can you help me sir?

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