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Brute force gmail hack
Tried with my account and my password in the file text but not working.
wordlist not from file
should pull from wordlist crunch command
crunch 4 6 0123456789xbyutfqui
It is not working, I tried with my own account (the one which I use to sign up for junk sites) and a wordlist which contained the correct password. Command prompt still displayed sorry
for every password in the list even for the right password.
what is the best solution of this problem .
plz help ,
Traceback (most recent call last):
File "/Users/admin/Desktop/Brute-force-gmail/gmail-3.py", line 79, in
instance.try_gmail()
File "/Users/admin/Desktop/Brute-force-gmail/gmail-3.py", line 33, in try_gmail
self.smtp.login(user,password)
File "/usr/local/Cellar/[email protected]/3.9.4/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 734, in login
(code, resp) = self.auth(
File "/usr/local/Cellar/[email protected]/3.9.4/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 637, in auth
(code, resp) = self.docmd("AUTH", mechanism + " " + response)
File "/usr/local/Cellar/[email protected]/3.9.4/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 427, in docmd
return self.getreply()
File "/usr/local/Cellar/[email protected]/3.9.4/Frameworks/Python.framework/Versions/3.9/lib/python3.9/smtplib.py", line 400, in getreply
raise SMTPServerDisconnected("Connection unexpectedly closed")
smtplib.SMTPServerDisconnected: Connection unexpectedly closed
doesn't show the password because it ets blocked by the google, and can't find which password in the list matches the gmail.
Password ?
I NEED SOLVE THIS PROPLEM PLEASE!
raceback (most recent call last):
File "/home/charon/Brute-force-gmail/gmail-4.py", line 81, in
instance.get_pass_list(senha)
File "/home/charon/Brute-force-gmail/gmail-4.py", line 20, in get_pass_list
file = open(path, 'r',encoding='utf8').read().splitlines()
File "/usr/lib/python3.10/codecs.py", line 322, in decode
(result, consumed) = self._buffer_decode(data, self.errors, final)
UnicodeDecodeError: 'utf-8' codec can't decode byte 0xf1 in position 5079973: invalid continu
It's quite useless, requires you to have "Less secure apps" enabled to work.
line 36
print((033[1;37mgood - %s % user + - %s 033[1;m % password ))
^
SyntaxError: leading zeros in decimal integer literals are not permitted; use an 0o prefix for octal integers
8.0.0
Man I have been at this for 3 days trying figure out and get this to work. Can you please just help me crack password for [email protected]
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