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Yogaht avatar Yogaht commented on July 24, 2024

请教一下,谢谢

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ypwhs avatar ypwhs commented on July 24, 2024

这是 Keras 的限制,Keras 要求训练的时候必须有一个输入和一个标签,通过优化输出和标签的差别来进行训练。但是我们这个问题里面要求输入 label、label_length、input_length,所以只能在 base_model 之外再搭建一个专门用于训练的模型,这个模型只输出 loss:model.compile(loss={'ctc': lambda y_true, y_pred: y_pred}, optimizer='adadelta') 因此这里的 y_true 是无意义的,只需要生成尺寸一致的矩阵就能通过 Keras 的检验。

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Yogaht avatar Yogaht commented on July 24, 2024

这是 Keras 的限制,Keras 要求训练的时候必须有一个输入和一个标签,通过优化输出和标签的差别来进行训练。但是我们这个问题里面要求输入 label、label_length、input_length,所以只能在 base_model 之外再搭建一个专门用于训练的模型,这个模型只输出 loss:model.compile(loss={'ctc': lambda y_true, y_pred: y_pred}, optimizer='adadelta') 因此这里的 y_true 是无意义的,只需要生成尺寸一致的矩阵就能通过 Keras 的检验。

好的,十分感谢!

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RenXiandong888 avatar RenXiandong888 commented on July 24, 2024

int(conv_shape[1]-2)
能问一下,这个地方为什么要减去2么?

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