Comments (5)
YeautyYE
commented on May 22, 2024
是什么场景需要获取到URL?
1.WebSocket启动时,客户端能连接到服务端的URL已经是确定的,不需要获取
2.如果一定要获取,可以在OnOpen时headers.get("host")获取host, 而path是写死在当前类的@ServerEndpoint中的
from netty-websocket-spring-boot-starter.
ernestmeng
commented on May 22, 2024
谢谢，已经解决了。我们是一个服务器，接不同视频流，有每个摄像头ip等参数，客户端连接过来也是需要有对应的ip才能推送相应的摄像头识别结果。另外问一下，这个是否支持作为client？现在只看到有ServerEndpoint注解，但是没有ClientEndpoint，我们当然是想使用同一种方式，不想一个应用中一会是基于netty的，一会是基于Tomcat的
from netty-websocket-spring-boot-starter.
YeautyYE
commented on May 22, 2024
目前没有,如果需要的话,可以邮件给你提供netty 写的websocket client demo
from netty-websocket-spring-boot-starter.
ernestmeng
commented on May 22, 2024
from netty-websocket-spring-boot-starter.
ernestmeng
commented on May 22, 2024
非常感谢
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