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y4h2 avatar y4h2 commented on August 27, 2024

tree的遍历类似于dfs的特殊情况。preorder, inorder, postorder相当于对于stack进出栈的不同讨论。
tree是分别处理左右子树, backtrack是处理for循环

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y4h2 avatar y4h2 commented on August 27, 2024

1079. Letter Tile Possibilities
通过Counter来避免生成重复值

class Solution:
    def numTilePossibilities(self, tiles: str) -> int:
        counter = Counter(tiles)
        self.result = 0
        
        def backtracking():
            self.result += 1
            for i in range(26):
                c = chr(ord('A') + i)
                if counter[c] == 0:
                    continue

                counter[c] -= 1

                backtracking()
                counter[c] += 1
                
        backtracking() 
        return self.result

也可以通过对字符串排序,然后控制index来避免重复

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