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ucchejbb avatar ucchejbb commented on July 24, 2024 1

min_press = results.node['head'][results.node['head']==results.node['head'].loc[53600].min()].loc[53600].dropna()

That should all be on one line (it currently breaks onto 2 lines as I'm typing).

When I try that with Net3.inp, I see 2 nodes with the minimum pressure at 5 hours. There might be a more elegant way to do that, but the results object is a pandas dataframe, so you can refer to their functions on how to interact with the data.

min_press.index returns the list of nodes that are at the minimum pressure.

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kaklise avatar kaklise commented on July 24, 2024 1

You can use results.node['pressure'].loc[:,wn.junction_name_list] to get pressure at junctions only.

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DanielaBS1 avatar DanielaBS1 commented on July 24, 2024

Thanks.
It did work fine. However I noticed I have junctions, emitters and tanks under nodes grupe. I was hoping to get the pressure at the junctions only. Do you know and easy way to do that?

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