Misleading example on December-01? about a-december-of-algorithms-2019 HOT 3 CLOSED

@atarv As I understand it, 350 is the correct 10th sevenish number.
The ten first sevenish numbers are as follows:
1 (7^0), 7 (7^1), 8, 49 (7^2), 50, 56, 57, 343 (7^3), 344, 350
You are missing 57, which is sum(1, 7, 49).
Admittedly, the wording of the problem and the given data are a little ambiguous.

from a-december-of-algorithms-2019.

Ah, I see. So a sevenish number is a sum of any (positive) number of unique powers of 7. Is that correct?

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@atarv yes, your definition of the problem is right. The ten first sevenish numbers pointed out by @alirezaghey is the correct one.

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