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pettermahlen avatar pettermahlen commented on August 17, 2024

You can use Stream operators, like so:

Stream<Route<?>> routes = Stream.of(route1, route2, route3)
     .map(route -> route.withMiddleware(myMiddleware));

That's a large reason we decided to go with Streams of Routes in the RoutingEngine methods; so as to avoid having to go back and forth between collections and streams when initialising applications. I have a slightly bad feeling about using streams this way (mostly because of terminal operations), but so far I'm not aware of any actual problems.

Please close if this answers your question!

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jonhkr avatar jonhkr commented on August 17, 2024

Thanks @pettermahlen I'll try that.

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