factors to character about janitor HOT 4 CLOSED

Would this be a function that converts all factor columns to characters? There's a purrr one-liner that seems to do that:
df %>% map_if(is.factor, as.character) -> df
(from here)

Would the function be more than that?

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Yeah, that's basically what I've been doing. It's been more challenging
than that one liner because I have been working with the mdb-get function
from Hmisc, which puts these S3 labels on every data frame... dmap_if
doesn't like it at all. See
https://github.com/almartin82/nyschooldata/blob/master/R/assess_db.R#L57
for more. Maybe this is just an edge case though.

On Aug 2, 2016 9:23 PM, "Sam" [email protected] wrote:

Would this be a function that converts all factor columns to characters?
There's a purrr one-liner that seems to do that:
df %>% map_if(is.factor, as.character) -> df
(from here
http://stackoverflow.com/questions/2851015/convert-data-frame-columns-from-factors-to-characters
)

Would the function be more than that?

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Is the Hmisc labelled class the same one produced by haven::read_sav()? I and a colleague both often want to go labelled -> factor. I used to have a janitor function for that, but I removed it. it felt too niche and I thought it might make haven a requirement of the package, though I'm new to understanding that part of package development. If a similar function would solve both of our problems, and it's a widespread issue with a non-trivial solution, I think a solution could be within scope.

My function was basically:

  labeled_var_index <- unlist(
    lapply(labels_df, function(x) class(x) == "labelled")
  )
  factorized <- labels_df
  factorized[, labeled_var_index] <- lapply(factorized[, labeled_var_index], as_factor)

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I haven't worked with it a ton yet but the sjlabelled package looks pretty robust for dealing with factor conversions. At this point I'd be surprised if this kind of functionality doesn't already exist elsewhere. Closing this as I clean up issues a bit.

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