I'm not sure how to traverse a parsed expression with version 2.1.1. For version 1.0.0

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Recommendations for traversing a parsed expression about filter-parser HOT 2 CLOSED

scim2 commented on June 19, 2024

Recommendations for traversing a parsed expression

from filter-parser.

Comments (2)

DagW commented on June 19, 2024 1

Thanks! The dereference was what was missing :-)

from filter-parser.

q-uint commented on June 19, 2024

Hey @DagW!

It works exactly the same way as before:

filter-parser/filter_test.go

Lines 72 to 95 in acaa319

 func Example_walk() { 

 expression, _ := ParseFilter([]byte("emails[type eq \"work\" and value co \"@example.com\"] or ims[type eq \"xmpp\" and value co \"@foo.com\"]")) 

 var walk func(e Expression) error 

 walk = func(e Expression) error { 

 switch v := e.(type) { 

 case *LogicalExpression: 

 _ = walk(v.Left) 

 _ = walk(v.Right) 

 case *ValuePath: 

 _ = walk(v.ValueFilter) 

 case *AttributeExpression: 

 fmt.Printf("%s %s %q\n", v.AttributePath, v.Operator, v.CompareValue) 

 default: 

 // etc... 

 } 

 return nil 

 } 

 _ = walk(expression) 

 // Output: 

 // type eq "work" 

 // value co "@example.com" 

 // type eq "xmpp" 

 // value co "@foo.com" 

 }

Let me know if there are more questions/problems.

from filter-parser.

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	func Example_walk() {
	expression, _ := ParseFilter([]byte("emails[type eq \"work\" and value co \"@example.com\"] or ims[type eq \"xmpp\" and value co \"@foo.com\"]"))
	var walk func(e Expression) error
	walk = func(e Expression) error {
	switch v := e.(type) {
	case *LogicalExpression:
	_ = walk(v.Left)
	_ = walk(v.Right)
	case *ValuePath:
	_ = walk(v.ValueFilter)
	case *AttributeExpression:
	fmt.Printf("%s %s %q\n", v.AttributePath, v.Operator, v.CompareValue)
	default:
	// etc...
	}
	return nil
	}
	_ = walk(expression)
	// Output:
	// type eq "work"
	// value co "@example.com"
	// type eq "xmpp"
	// value co "@foo.com"
	}

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