shallow copy don't work as expected about rlang HOT 4 CLOSED

I'm not sure what you're expecting here. But please note that rlang::duplicate() is for expert usage only. It's a direct wrapper around the C-level function of the R API which most certainly works as expected according to its specifications.

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Thank you for the clarification. I understand that rlang::duplicate() is a powerful function that directly wraps a C-level function in the R API. I mean the names of dt1 shouldn't change when I change dt2 by reference just like what dt3 worked. dt3 is a data.table created via dt1[TRUE] which has been revealed to do shallow copy.

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dt2 has removed the name "mpg" in dt1

dt2[, mpg := NULL]
x
#>  [1] "cyl"  "disp" "hp"   "drat" "wt"   "qsec" "vs"   "am"   "gear" "carb"
names(dt1)
#>  [1] "cyl"  "disp" "hp"   "drat" "wt"   "qsec" "vs"   "am"   "gear" "carb"

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It's not that it's powerful, it's that it's extremely low level, and you shouldn't expect any high level semantics from it. Also it's mostly meant for prototyping C code from R and should generally not be used in user or package code.

dt2 has removed the name "mpg" in dt1

Yes since it's a shallow copy the attributes list is not duplicated, which means that if you modify the names in place later on you'll get side effects. It's all working as expected from the perspective of these very low level tools.

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