Question: How do I increase the number of new lines to two before a heading? about obsidian-linter HOT 7 CLOSED

Hey @AndreiSager . The Linter does not directly support this use case. However it does allow you to use custom regex for this situation. How familiar are you with regex?

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Thanks for responding! I am not familiar with regex, but I have heard of it.

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For those reading this, these are the steps necessary to make this happen:

1. Open Settings > Linter > Custom
2. Add new regex replacement, do the following:

• regex to find: ([^ \t\r\n\v\f])\n(#)
• gm
• regex to replace: $1\n\n$2

from obsidian-linter.

For those reading this, these are the steps necessary to make this happen:

1. Open Settings > Linter > Custom
2. Add new regex replacement, do the following:

• regex to find: ([^ \t\r\n\v\f])\n(#)
• gm
• regex to replace: $1\n\n$2

Thank you for your solution! I have tried it and it is not working. Am I supposed to disable or enable a setting to make it work?

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The regex you need will be based on the following logic in the code:

      text = text.replace(/^(#+\s.*)/gm, '\n\n$1\n\n'); // add blank line before and after headings
      text = text.replace(/\n+(#+\s.*)/g, '\n\n$1'); // trim blank lines before headings
      text = text.replace(/(^#+\s.*)\n+/gm, '$1\n\n'); // trim blank lines after headings
    }

    text = text.replace(/^\n+(#+\s.*)/, '$1'); // remove blank lines before first heading
    text = text.replace(/(#+\s.*)\n+$/, '$1'); // remove blank lines after last heading

So if you want to make it so that all headings have something like /^(#+\s.*)/gm and the \n\n\n$1 for the replace.
Then you need to trim blank lines before headings if they are too long: /\n{2,}(#+\s.*)/g for find and \n\n\n$1 for replace.
Lastly, you nedd to remove the blank lines before the first heading:
^\n+(#+\s.*) and the replace $1 and make sure it has no flags.

Thus it looks something like this:

Note: I have not tested this and cannot really do so at this time. But hopefully this gets you roughly to wherw you need to be.

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@pjkaufman Thank you very much for helping solve my problem! The solution you gave works wonders!

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I am glad that it works!

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