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panthernet avatar panthernet commented on June 19, 2024 1

Hi. First of all, run GenerateGraph method inside the Loaded event handler for control to ensure that rendering surface is ready. And as of MVVM you have to only maintain LogicCore in your model and then bind it to corresponding property of GraphArea. So you don't have to create new GraphArea object in a viewmodel.

And if you do it your way the
Rga1 = ((dynamic)this.DataContext).RhythmGraphArea;
will likely won't work. Don't declare GraphArea in XAML but name its container (zoomcontrol) and then add GraphArea from viewmodel into ZoomControl content instead of assigning GrpahArea to existing object.

from graphx.

manchuwook avatar manchuwook commented on June 19, 2024

Ah! Thanks - using just LogicCore definitely simplifies it. If I don't load the GraphArea in XAML though, how would I style it?

from graphx.

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