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Comments (2)

attack68 avatar attack68 commented on September 22, 2024

This is quite an esoteric use. Not particularly enthusiastic about adding a pandas option for this functionality.

You can directly instantiate a Styler with a specified id

from pandas.io.formats.style import Styler
styler = Styler(df, uuid="my_id")

can be used instead of:

styler = df.style

Alernatively create a factory:

def styler(df):
    return Styler(df, uuid="default_id")

styler(df)

from pandas.

thisiswhereitype avatar thisiswhereitype commented on September 22, 2024

Okay thanks for the comments - I can use a factory.

from pandas.

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