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waterm310n avatar waterm310n commented on June 9, 2024 1

以我的理解,在你所举的例子中B当前的任期是1,状态时Follower或者Leader,它的log如下
LogIndex:0 Cmd:Nil Term:0|LogIndex:1 Cmd:any Term:1|LogIndex:2 Cmd:any Term:1
A当前的任期是2,状态是Candidate,它的log如下
LogIndex:0 Cmd:Nil Term:0|LogIndex:1 Cmd:any Term:1|
你的意思是有可能存在另一个C它与B是相同的日志,然后因为符合大多数原则,所以C与B应用了LogIndex1,2,所以此时如果同意A的投票请求,就会出错。
作者的isLogUpToDate方法接受了两个参数LastLogIndexLastLogTerm,应该就足够实现这个逻辑了吧?
B可以检查完Term后,拿自己的LastLogIndex与A的LastLogIndex相比,发现比A的大,isLogUpDate就可以返回false了吧?

from mit6.824-2021.

Amadeus-1048 avatar Amadeus-1048 commented on June 9, 2024

以我的理解,在你所举的例子中B当前的任期是1,状态时Follower或者Leader,它的log如下 LogIndex:0 Cmd:Nil Term:0|LogIndex:1 Cmd:any Term:1|LogIndex:2 Cmd:any Term:1 A当前的任期是2,状态是Candidate,它的log如下 LogIndex:0 Cmd:Nil Term:0|LogIndex:1 Cmd:any Term:1| 你的意思是有可能存在另一个C它与B是相同的日志,然后因为符合大多数原则,所以C与B应用了LogIndex1,2,所以此时如果同意A的投票请求,就会出错。 作者的isLogUpToDate方法接受了两个参数LastLogIndexLastLogTerm,应该就足够实现这个逻辑了吧? B可以检查完Term后,拿自己的LastLogIndex与A的LastLogIndex相比,发现比A的大,isLogUpDate就可以返回false了吧?

是的,我的理解有误,A节点的任期大不代表其日志的任期也更大,感谢解答。

from mit6.824-2021.

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