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Comments (3)

mateusneresrb avatar mateusneresrb commented on August 16, 2024

It ends up in the Double.parseDouble of this class and removes the 0. The correct thing to do would be to return a BigDecimal, but this scenario only occurs with a string longer than 18 characters.

json-smart-v2/json-smart/src/main/java/net/minidev/json/parser/JSONParserBase.java

Lines 152 to 180 in 4b1a6b5

protected Number extractFloat() throws ParseException {
if (!acceptLeadinZero)
checkLeadinZero();
try {
if (!useHiPrecisionFloat)
return Float.parseFloat(xs);
// follow JSonIJ parsing method
if (xs.length() > 18) {
// use extra CPU to check if the result can be return as double without
// precision lost
if (!unrestictBigDigit) {
double asDouble = Double.parseDouble(xs);
final String doubleStr = String.valueOf(asDouble);
// we need a compare `e` `E` `e+` `E+`
if (compareDoublePrecision(doubleStr, xs)) {
return asDouble;
}
}
return new BigDecimal(xs);
}
return Double.parseDouble(xs);
} catch (NumberFormatException e) {
throw new ParseException(pos, ERROR_UNEXPECTED_TOKEN, xs);
}
}

from json-smart-v2.

UrielCh avatar UrielCh commented on August 16, 2024

10.50 and 10.5 are the same value.
fill free to re-format flot number to keep extra tailling zero, or store you digits as string.

from json-smart-v2.

mateusneresrb avatar mateusneresrb commented on August 16, 2024

10,50 e 10,5 são o mesmo valor. preencha livre para reformatar o número do flot para manter o zero de rejeitos extras ou armazene seus dígitos como string.

I see, they're the same value, but after I turn it into a bigdecimal, because I need the 0, it ends up removing it. One option would be to use a custom mapper?

from json-smart-v2.

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