Comments (4)
Hello @acesme ,
thank you for your comment!
As a matter of fact, it's a really good question. I would say (or suggest) it shouldn't.
In the moment, the low level _putchar()
function is responsible for the printf()
output, so any \0 could be filtered out easily.
Normally the plain native printf()
is used to output strings to the screen or a terminal and a terminator isn't needed or even unwanted.
Have to check it... Any other opinions/suggestions here?
from printf.
Yes, it is simple to filter out the final '\0'
in the _putchar()
implementation.
It is also possible (albeit a little hacky) to fix this on 653rd row of printf.c by checking if out == _out_char
and opting to not append the '\0'
(or something like that).
I have no other suggestions that I can think of for now.
from printf.
I think, it's better to "fix" this in _out_char() itself, so other output functions won't get any penalty, something like
static inline void _out_char(char character, char* buffer, size_t idx, size_t maxlen)
{
(void)buffer; (void)idx; (void)maxlen;
if (character) {
_putchar(character);
}
}
from printf.
I think, suppressing the terminating \0
is conform to the standard.
@acesme, thanx for bringing this to attention. Fixed.
from printf.
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from printf.