problem with paths on Linux about wav2lip_extension HOT 4 CLOSED

What error message is it showing? It can't find the path? Is it because the wrong slash in the path?

from wav2lip_extension.

In code, I have referenced, there is no Python error. The error shows later when this file is going to be accessed. This is because of incorrectly computed path.

The char \ is used inside string. This works on Windows - the char is interpreted as a folder separator.
But on Linux this is a totally valid filename, so there is created a folder with name wav2lip\checkpoints.

https://docs.python.org/3/library/os.html?highlight=os.sep#os.sep

from wav2lip_extension.

I updated https://github.com/Mozer/wav2lip, removed those back slashes and wrapped in os.path.join. Please check if it works now, maybe I missed something.

from wav2lip_extension.

I have reviewed these changes and it looks good.
I believe that trailing "" (empty string) is not necessary, because flask function send-from-directory do not care about it (it is actually passed again to os.path.join), but let it stay for now.

from wav2lip_extension.