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Comments (5)

LittleBeannie avatar LittleBeannie commented on June 26, 2024

Test plan for assign_lable:

  • It gives an error message when you run
tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3))
assin_label(tbl, var = "a", label = c("variable 1", "variable 2"))
  • It gives an error message when you run
tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3))
assin_label(tbl, var = c("a", "a"), label = c("variable 1", "variable 2"))
  • It gives a warning message when you run
tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3))
assin_label(tbl, var = "a", label = "variable 1")
  • After running the following code, the labels of tbl is "variable 1", "variable 2"
tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3))
assin_label(tbl, var = c("a", "b"), label = c("variable 1", "variable 2"))
```

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ginnaram13 avatar ginnaram13 commented on June 26, 2024

Hi @LittleBeannie

Can you check why the label is not assigning for below;

tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3))
assign_label(tbl, var = c("a", "b"), label = c("variable 1", "variable 2"))

image

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LittleBeannie avatar LittleBeannie commented on June 26, 2024

Hi @LittleBeannie

Can you check why the label is not assigning for below;

tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3)) assign_label(tbl, var = c("a", "b"), label = c("variable 1", "variable 2"))

image

Hi @ginnaram13 , please try tbl$a and you will find a's label is variable 1.

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ginnaram13 avatar ginnaram13 commented on June 26, 2024

Hi @LittleBeannie
Can you check why the label is not assigning for below;
tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3)) assign_label(tbl, var = c("a", "b"), label = c("variable 1", "variable 2"))
image

Hi @ginnaram13 , please try tbl$a and you will find a's label is variable 1.

@LittleBeannie
No Luck for me
image

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ginnaram13 avatar ginnaram13 commented on June 26, 2024

Hi @LittleBeannie
Can you check why the label is not assigning for below;
tbl <- data.frame(a = c(1, 2, 3), b = c(-1, -2, -3)) assign_label(tbl, var = c("a", "b"), label = c("variable 1", "variable 2"))
image

Hi @ginnaram13 , please try tbl$a and you will find a's label is variable 1.

@LittleBeannie No Luck for me image

image

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