Comments (7)
I think case object
s already extend Serializable
by default, so the problem might be as you said; the lack of a no-args constructor on the parent.
Perhaps something like this could work?
sealed trait PhBoardingStatus extends EnumEntry
object PhBoardingStatus extends Enum[PhBoardingStatus] {
val values = findValues
case object All extends PhBoardingStatus { override val entryName = "ALL"}
case object Closed extends PhBoardingStatus { override val entryName = "BC" }
case object Ignored extends PhBoardingStatus { override val entryName = "BI" }
case object NotOpen extends PhBoardingStatus { override val entryName = "BN" }
case object Open extends PhBoardingStatus { override val entryName = "BO" }
case object Suspended extends PhBoardingStatus { override val entryName = "BS" }
}
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I've added this in the sealed abstract class instead, which I find less verbose and seems to work fine too:
def this() = this("")
Yet I'm not familiar enough with this to understand why we need this no-param constructor and if it could be fixed directly in the EnumEntry...
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I'm gonna try this and will let you know if it works. Thanks for the tip!
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I also had such problem. I think it must be fixed because it mays API very verbose
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@lloydmeta your solution works but it leave the code more verbose unnecessarily. Is there a better fix for this situation?
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The problem is the lack of a no-arg constructor, which is required for Java Serialisation to work.
If you don't need to customise the entryName
, then a simple argument-free abstract class
extending EnumEntry
might work too.
@kantlove @antonkulaga if you have other ideas, send PRs.
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Hi,
I had the same problem but with my enum extending enumeratum.EnumEntry.Lowercase
trait. I think that the problem is the same because Lowercase
trait overrides the entryName
too.
I have chosen the def this() = this("")
option to resolve the problem because it is less verbose.
Thanks @tsabran
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