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Comments (4)

lipoja avatar lipoja commented on July 24, 2024

Hi, thank you for reporting this issue. I really appreciate your time doing it.
I assume that it is similar to #57 which is already fixed in master branch.

The code that is in master would return:

a=extractor.find_urls("http://[email protected]:51733/hn35/")
print(a) # "[http://[email protected]:51733/hn35/]"  <- this is valid URL

from urlextract.

Phantomdft avatar Phantomdft commented on July 24, 2024

Ok.I got it

from urlextract.

Phantomdft avatar Phantomdft commented on July 24, 2024

print(a) # "[http://[email protected]:51733/hn35/]" <- this is valid URL

And this is not a valid URL,the host before "@" is actually auth part of url(scheme:[//authority]path[?query][#fragment]).This host is uint(a) # "[http://[email protected]:51733/hn35/]" <- this is valid URL

And this is not a valid URL,the host before "@" is actually auth part of url(scheme:[//authority]path[?query][#fragment]).This host is usually used for url derect cheating

from urlextract.

lipoja avatar lipoja commented on July 24, 2024

I agree that that the part before @ is used for authentication. But there is nothing invalid on that URL according to RFC. Therefore I've wrote that it is valid URL. And yes I agree, these kind of URL are usually used for phishing or other kind of web threat.

from urlextract.

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