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JosephP91 avatar JosephP91 commented on May 18, 2024

@tucanus Hi and thank you for using curlcpp!
Try to change this line:

auto pippo = easy.get_info(CURLINFO_COOKIELIST);

with this:

auto pippo = easy.get_info<vector<string>>(CURLINFO_COOKIELIST);

get_info is a template method in which you have to specify the type. Let me know!

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tucanus avatar tucanus commented on May 18, 2024

Sorry, it is true, my mistake.
Ok, now it compiles, but does not work, get_info throws an exception and error.print_traceback() shows
ERROR: A libcurl function was given a bad argument ::::: FUNCTION: get_info<std::vector<std::basic_string<char> > >

I suspect code of get_info being incorrect (curl_easy_getinfo third parameter shoul be struct curl_slist **, you should check ptr != nullptr before applying ->next field, and should not infer that struct curl_slist elements being of same dimensions, hence I suggest to correct get_info this way (it works on my PC ;)

// Putting the namespace here will avoid the "specialization in different namespace" error.
namespace curl {
    template<> std::unique_ptr<std::vector<std::string>> curl_easy::get_info(const CURLINFO info) const {
        struct curl_slist *ptr = nullptr;
        const CURLcode code = curl_easy_getinfo(this->curl,info,&ptr);
        if (code != CURLE_OK) {
            curl_slist_free_all(ptr);
            throw curl_easy_exception(code,__FUNCTION__);
        }
        std::vector<std::string> infos;

        struct curl_slist *list = ptr;
        while (list != nullptr) {
            infos.push_back(std::string(list->data));
            list = list->next;
        }
        curl_slist_free_all(ptr);
        return std::unique_ptr<std::vector<std::string>>{new std::vector<std::string>(infos)};
    }
}

Thank you for your support and your time.

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JosephP91 avatar JosephP91 commented on May 18, 2024

@tucanus Yeah, right! Now it works also on my environment! Thank you! If everything works, you can close the issue. For anything else, let me know! I will update the repo as soon as possible.

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