Comments (5)
map
is basically transform
. I think you want to call for_each
: https://godbolt.org/z/vz9Gqdavr
from kumi.
In this case I have a zip-like thing happening and really do want map-like functionality.
std::vector<int> a, b, c, d;
kumi::tuple l = { std::ref(a), std::ref(b) };
kumi::tuple r = {std::ref(c), std::ref(d) };
kumi::map([](auto&& l, auto&& r) {
return l[0] = r[0]; // don't want to return
}, l, r);
from kumi.
It's possible that this should just be a separate function named zip_with
.
from kumi.
I fail to see how
kumi::map([](auto&& l, auto&& r) {
return l[0] = r[0]; // don't want to return
}, l, r);
is not:
kumi::for_each([](auto&& l, auto&& r) {
l[0] = r[0];
}, l, r);
Is that you want it to be called map? I mean, it's not rly map.
from kumi.
If for_each
supports zipping then that’s what I want. I don’t want map
, that was my original complaint.
I’m unfamiliar with the use of algorithms called for_each
that provide this zip
functionality. I think it’s more traditionally called zip_with
. Now I know what kumi
calls it is though, I’m happy.
from kumi.
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