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Linearity avatar Linearity commented on May 22, 2024 1

The combined signal functions are recursively switching to each other because they both produce a trigger event at time 3. Using a delayed combinator is no help because

  1. it does not change the input, and
  2. the signal functions before and after the switch are the same, so their output is the same.

The solution is to pass the trigger event signal through notYet, which suppresses events at local time 0. Therefore the first signal function will switch at time 3 (local time 3) and the second signal function will not switch at time 3 (local time 0).

from yampa.

ziriax avatar ziriax commented on May 22, 2024

It had been a decade since I did Haskell, so my answer might be silly and wrong. But it seems you are switching into the same list of actors.

(\colSfs _ -> swit colSfs)

Could you try

(\(_:colSfs) _ -> swit colSfs)

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DavidEichmann avatar DavidEichmann commented on May 22, 2024

So that would solve the infinite loop, but it isn't the behaviour I am looking for: I need to keep the actor. What I ultimately want is for actors to be able to spawn new actors, so the code would actually look more like this:

(\colSfs _ -> swit (eventAt3 : colSfs))

which would make the situation even worse.

from yampa.

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