Comments (3)
Thanks for your interest in our project. np.where
gives a list of indices where the input condition is true. Thus, len(np.where([...])
would give us the number of completed tasks in that interval for which the destroy time is higher than the service level agreement.
from cosco.
Thank you very much for your reply. I understand what it means. But writing like this will result in len(np.where([...])
can only be 1 each time, no matter how many c.destroyAt > c.sla
. The output of an example is as follows.
destroyed = []
[c.destroyAt > c.sla for c in destroyed] output is: []
np.where([c.destroyAt > c.sla for c in destroyed]) output is: (array([], dtype=int64),)
len(np.where([c.destroyAt > c.sla for c in destroyed])) output is : 1
But, what I understand is, when destroyed = []
, the slaviolations should be 0. So I think there is something wrong with the code. Or is my understanding of slaviolations wrong?
Hope to hear from you.
from cosco.
Thanks for raising this. It has been fixed.
from cosco.
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