Comments (7)
I'm not sure I follow. The result is a regular javascript object.
Can you give me any details of what you're trying to do?
Original comment by [email protected]
on 24 Apr 2009 at 1:26
from json-sans-eval.
give example
Original comment by [email protected]
on 28 Apr 2009 at 9:09
from json-sans-eval.
[deleted comment]
from json-sans-eval.
Yeah.I'm really way beyond this at this point.. But you don't give any usage
examples like every other script
on the Internet. To you it may seem obvious, since you wrote it and are
probably a javascript wiz, but many
people who are just dipping their toes into json may not know exactly what to
do with it. Even if it is just a
regular js object.
Original comment by [email protected]
on 28 Apr 2009 at 12:07
from json-sans-eval.
Just use it as an array. If you have:
var myJsonObj = { {"param1": 100}, {"param2": 200 } };
then you can do:
alert(myJsonObj[param1]);
or you can loop through it:
for( var x in myJsonObj ) {
alert( x ); //This prints out "param1" and "param2"
alert( myJsonObj[x] ); //This prints out 100 and 200
}
Original comment by [email protected]
on 22 Jun 2009 at 2:15
from json-sans-eval.
awesome
Original comment by [email protected]
on 22 Jun 2009 at 9:54
from json-sans-eval.
This issue did not contain a bug report so closing. I will add some usage
examples
though.
Original comment by [email protected]
on 2 Sep 2009 at 3:00
- Changed state: Invalid
from json-sans-eval.
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