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GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
I'm not sure I follow.  The result is a regular javascript object.
Can you give me any details of what you're trying to do?

Original comment by [email protected] on 24 Apr 2009 at 1:26

from json-sans-eval.

GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
give example 

Original comment by [email protected] on 28 Apr 2009 at 9:09

from json-sans-eval.

GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
[deleted comment]

from json-sans-eval.

GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
Yeah.I'm really way beyond this at this point.. But you don't give any usage 
examples like every other script 
on the Internet. To you it may seem obvious, since you wrote it and are 
probably a javascript wiz, but many 
people who are just dipping their toes into json may not know exactly what to 
do with it. Even if it is just a 
regular js object.

Original comment by [email protected] on 28 Apr 2009 at 12:07

from json-sans-eval.

GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
Just use it as an array. If you have:

var myJsonObj = { {"param1": 100}, {"param2": 200 } };

then you can do:

alert(myJsonObj[param1]);

or you can loop through it:

for( var x in myJsonObj ) {
    alert( x );  //This prints out "param1" and "param2"
    alert( myJsonObj[x] ); //This prints out 100 and 200
}

Original comment by [email protected] on 22 Jun 2009 at 2:15

from json-sans-eval.

GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
awesome

Original comment by [email protected] on 22 Jun 2009 at 9:54

from json-sans-eval.

GoogleCodeExporter avatar GoogleCodeExporter commented on July 28, 2024
This issue did not contain a bug report so closing.  I will add some usage 
examples
though.

Original comment by [email protected] on 2 Sep 2009 at 3:00

  • Changed state: Invalid

from json-sans-eval.

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