Q: is there a way to print an object's memory address in Eiffel? about gobo HOT 7 CLOSED

Do you mean the size of the object in memory?

from gobo.

No, the object's address, in C / C++, for struct Object object I want &object.

from gobo.

Try that:

	f
		local
			s: STRING
		do
			s := "gobo"
			print ($s)
		end

Note that when compiled with ISE Eiffel, the garbage collector may move objects in memory.

from gobo.

print ? Any IO class need to be inherited from?

tried:

io.put_string  ($(zone.implementation))
io.put_integer ($(zone.implementation))

ISE eiffel all reported: Syntax error.

BTW, any io.put_hex_integer method?

from gobo.

print comes from ANY:

	print (o: detachable ANY)
			-- Write terse external representation of `o'
			-- on standard output.
		local
			s: READABLE_STRING
		do
			if attached o then
				s := o.out
				if attached {READABLE_STRING_32} s as s32 then
					io.put_string_32 (s32)
				elseif attached {READABLE_STRING_8} s as s8 then
					io.put_string (s8)
				else
					io.put_string_32 (s.as_string_32)
				end
			end
		ensure
			instance_free: class
		end

$s is of type POINTER, so io.put_string or io.put_integer will not work. There is no io.put_hex_integer as far as I know.

from gobo.

I can do print($zone), but cannot do print($(zone.implementation)) got Syntax error.

have to add local vars:

                        impl, impl2: EV_WIDGET_I

                        impl := zone.implementation
                        impl2 := zone.implementation_upper_zone
                        print($impl)
                        io.put_string("%N")
                        print($impl2)
                        io.put_string("%N")

Now, it works.

This syntax sucks.

from gobo.

I can do print($zone), but cannot do print($(zone.implementation)) got Syntax error.

It works with gec.

This syntax sucks.

You are not supposed to access object addresses in Eiffel in the first place. Eiffel is not C :-)

from gobo.