Comments (1)
// BFS迭代法
- 初始化队列,并存入两颗树的根节点
- 遍历两棵树的节点,依次入队root1.left, root2.left, root1.right, root2.right
- 对出队节点校验:
- 如果一个有一个为空,返回 false
- 如果两个节点的 val 不同,返回 false
- 如果两个节点都为 null,跳过
var isSameTree = function(p, q) {
if(!p && !q){
return true
}
let queue = [p, q];
while(queue.length){
let root1 = queue.shift();
let root2 = queue.shift();
if(!root1 && !root2) {
continue;
}
if(root1 && root2 && root1.val !== root2.val){
return false
}
if(!root1 || !root2){
return false
}
queue.push(root1.left, root2.left);
queue.push(root1.right, root2.right);
}
return true;
}
from javascript-leetcode.
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from javascript-leetcode.