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lywq9296 avatar lywq9296 commented on August 21, 2024

// BFS迭代法

  1. 初始化队列,并存入两颗树的根节点
  2. 遍历两棵树的节点,依次入队root1.left, root2.left, root1.right, root2.right
  3. 对出队节点校验:
  4. 如果一个有一个为空,返回 false
  5. 如果两个节点的 val 不同,返回 false
  6. 如果两个节点都为 null,跳过
var isSameTree = function(p, q) {
  if(!p && !q){
    return true
  }
  let queue = [p, q];
  while(queue.length){
    let root1 = queue.shift();
    let root2 = queue.shift();

    if(!root1 && !root2) {
      continue;
    }

    if(root1 && root2 && root1.val  !==  root2.val){
      return false
    }
    
    if(!root1 || !root2){
      return false
    }
	
    queue.push(root1.left, root2.left);
    queue.push(root1.right, root2.right);
  }
  return true;
}

from javascript-leetcode.

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