Interface type property not return created object about fakeiteasy HOT 3 CLOSED

Hi, @iozcelik.

        A.CallTo(() => userManager
           .Find(f => f.UserName.Equals("John", StringComparison.InvariantCultureIgnoreCase)))

sets up an expectation on a lambda: () => userManger…. So FakeItEasy compares that lambda against any received arguments later on (see Argument Contraints). But the lambda has no value-based Equals method, so it's compared to see if it's the same instance. Which it isn't. This has been asked on StackOverflow before. It's not exactly your situation, but How to test for a Match with FakeItEasy on a predicate call? is very close. Check out my answer there for more info.

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Hi @blairconrad ,

Thanks after your answer, I solve the problem. I just change the my code:

A.CallTo(() => permisionManager.UserManager.Find(A<Expression<Func<User, bool>>>.That
        .Matches(exp => Expression.Lambda<Func<string>>(((MethodCallExpression)exp.Body).Arguments[0]).Compile().Invoke() == "John")))
        .Returns(new User() {
            Id = "1",
            UserName = "John"
        });

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Glad you're working again, @iozcelik.

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