Comments (1)
otakustay
commented on May 28, 2024
在对象式编程的情况下，Action是一个构造函数，此时Action就是一个函数。在这种情况下，很难区分一个函数是作为构造函数，还是直接当Action使用。一种方式是根据 函数名首字母是否大写 来判断，但框架并不希望添加过多的规范上的限制。
另一方面，现有的框架已经支持任何包含enter方法的对象作为Action，因此只需要将一个函数作为一个纯对象的enter方法即可，不会产生太多的工作量。
因此，暂不考虑支持这一功能。如果切实有产品线对此有迫切需求，可以重新打开本Issue。
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