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dmendel avatar dmendel commented on July 30, 2024

from bindata.

catlee avatar catlee commented on July 30, 2024

I was hoping that since a record defines its fields from least to most significant bytes, and that you can mix the endianness between different byte fields, that I would be able to do the same within a bitfield. In the example above I would expect that :tag would use the 2 most significant bits of the byte, and :a would use the 6 least significant bits.

76543210
ttaaaaaa

The docs kind of imply this is possible: https://github.com/dmendel/bindata/wiki/Records#specifying-default-endian. Perhaps a note could be added there (or in the section about bitfields) that you can't mix endian-ness?

Should the endian directive apply for records containing bitfields?

from bindata.

dmendel avatar dmendel commented on July 30, 2024

from bindata.

catlee avatar catlee commented on July 30, 2024

Yes, that would be the expected output regardless of the endianness of the bitfield, right?

These two classes give the same result

class Test1 < BinData::Record
  bit2 :tag 
  bit6 :a
end

class Test2 < BinData::Record
  bit6le :a 
  bit2le :tag 
end

Test1.read("\xa4") == Test2.read("\xa4")

For the same sequence of bits bitN(bits) == bitNle(bits). If I'm understanding things correctly, the difference is if the bits are consumed starting from the beginning or end of the byte(s)?

In any case, I don't want to belabour the point. Thank you for explaining things!

from bindata.

dmendel avatar dmendel commented on July 30, 2024

from bindata.

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