Chain combinator question about superpower HOT 2 CLOSED

Hi Christof, thanks for the note. Chain() seems like the right overall approach - I wonder whether we could make the signature a bit more flexible? Are you able to experiment by creating a modified "chain" in your own solution that accepts Func<TOperator, T, U, T> or similar? Cheers!

from superpower.

I solved it now through a combination of combinators and the .NET Aggregate method.

           from v in Variable
           from props in (
               from _ in Token.EqualTo(FilterExpressionToken.Dot)
               from p in Token.EqualTo(FilterExpressionToken.Identifier)
               select p
            ).Many()
           select 
                props.Aggregate(v, (e, p) => FilterExpression.PropertyGetter(e, p.Span.ToStringValue()));

I will try to send a pull request when/if I succeed with an overloaded Chain that takes Func<TOperator, T, U, T>.

from superpower.