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Comments (4)

D-X-Y avatar D-X-Y commented on May 18, 2024

Sure, we use the hard mode and thus it is a one-shot vector. Something like this in PyTorch:

y_soft = Gumbel Softmax( ... )
y_hard = one_hot( y_soft )
y_hard = y_hard - y_soft.detach() + y_soft

During the forward, you could use:

cals = []
for i, w in enumerate(y_hard):
  if w.item() == 1:
    cals.append( op[i](x) * w )
  else:
    cals.append( x )
return sum(cals)

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coolKeen avatar coolKeen commented on May 18, 2024

Sure, we use the hard mode and thus it is a one-shot vector. Something like this in PyTorch:

y_soft = Gumbel Softmax( ... )
y_hard = one_hot( y_soft )
y_hard = y_hard - y_soft.detach() + y_soft

How do you implement the backward process?

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D-X-Y avatar D-X-Y commented on May 18, 2024

If you implement forward in the above style, it can automatically backward in PyTorch.

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brdav avatar brdav commented on May 18, 2024

Sure, we use the hard mode and thus it is a one-shot vector. Something like this in PyTorch:

y_soft = Gumbel Softmax( ... )
y_hard = one_hot( y_soft )
y_hard = y_hard - y_soft.detach() + y_soft

During the forward, you could use:

cals = []
for i, w in enumerate(y_hard):
  if w.item() == 1:
    cals.append( op[i](x) * w )
  else:
    cals.append( x )
return sum(cals)

Thanks for the code snippet!
Why would you append x for the paths with weight 0? Shouldn't there be no forward propagation?

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